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September 11, 2013
September 7, 2013
Useful Electrical Equations!
Useful Electrical Equations:
· For Sinusoidal Current: Form Factor = RMS Value/Average Value = 1.11
· For Sinusoidal Current: Peak Factor = Max Value/RMS Value = 1.414
· Average Value of Sinusoidal Current (Iav) = 0.637 x Im (Im = Max.Value)
· RMS Value of Sinusoidal Current (Irms) = 0.707 x Im (Im = Max.Value)
· A.C Current = D.C Current/0.636.
· Phase Difference between Phase = 360/ No of Phase (1 Phase=230/1=360°, 2 Phase=360/2=180°)
· Short Circuit Level of Cable in KA (Isc) = (0.094 x Cable Dia in Sq.mm) /√ Short Circuit Time (Sec)
· Max.Cross Section Area of Earthing Strip (mm2) = √(Fault Current x Fault Current x Operating Time of Disconnected Device ) / K
K = Material Factor, K for Cu = 159, K for Al = 105, K for steel = 58 , K for GI = 80
· Most Economical Voltage at given Distance = 5.5 x √ ((km/1.6) + (kw/100))
· Cable Voltage Drop (%) =
(1.732 x current x (RcosǾ+jsinǾ) x 1.732 x Length (km) x 100) / (Volt(L-L) x Cable Run.
· Spacing of Conductor in Transmission Line (mm) = 500 + 18 x (P – P Volt) + (2 x (Span in Length)/50).
· Protection radius of Lighting Arrestor = √h x (2D-h) + (2D+L).
Where h= height of L.A, D-distance of equipment (20, 40, 60 Meter), L=V x t (V=1m/ms, t=Discharge Time).
· Size of Lighting Arrestor = 1.5x Phase to Earth Voltage or 1.5 x (System Voltage/1.732).
· Maximum Voltage of the System = 1.1xRated Voltage (Ex. 66KV = 1.1 × 66 = 72.6KV)
· Load Factor = Average Power/Peak Power
· If Load Factor is 1 or 100% = This is best situation for System and Consumer both.
· If Load Factor is Low (0 or 25%) = you are paying maximum amount of KWH consumption. Load Factor may be increased by switching or use of your Electrical Application.
· Demand Factor = Maximum Demand / Total Connected Load (Demand Factor <1)
· Demand factor should be applied for Group Load
· Diversity Factor =
Sum of Maximum Power Demand / Maximum Demand (Demand Factor >1)
Diversity factor should be consider for individual Load
· Plant Factor (Plant Capacity) = Average Load / Capacity of Plant
· Fusing Factor = Minimum Fusing Current / Current Rating (Fusing Factor>1).
· Voltage Variation (1 to 1.5%) = ((Average Voltage – Min Voltage) x 100)/Average Voltage
Ex: 462V, 463V, 455V, Voltage Variation= ((460 – 455) x 100)/455 = 1.1%.
· Current Variation (10%) = ((Average Current – Min Current) x 100)/Average Current
Ex: 30A,35A,30A, Current Variation = ((35-31.7) x 100)/31.7 = 10.4%
· Fault Level at TC Secondary
= TC (VA) x 100 / Transformer Secondary (V) x Impedance (%)
Motor Full Load Current = Kw /1.732 x KV x P.F x Efficiency
August 29, 2013
Sometimes we have seen that a ceiling fan suddenly starts moving in opposite direction with slow speed, what could be the defect?
The starting winding circuit is open-circuited may be due to burnt winding or damaged capacitor or the running winding is damaged. The fan is running only on one winding. The blades and thrust of air in the room accelerated the blades in opposite direction. As we know that the single phase motors are not self-starting, they will continue to move in the direction in which these are initially accelerated.
July 12, 2013
What are the Functions of Substation Equipment?
Functions of Substation Equipments:
Sl. No.
|
Equipment
|
Function
|
|
Bus-Bar
|
Incoming & outgoing circuits Connected to bus-bar
|
|
Circuit
Breaker
|
Automatic switching during normal
or abnormal conditions
|
|
Isolators
|
Disconnection under no-load
condition for safety, isolation and maintenance.
|
|
Earthing
switch
|
To discharge the voltage on deadlines
to earth
|
|
Current
Transformer
|
To step-down currents for
measurement, control & protection
|
|
Voltage
Transformer
|
To step-down voltages for
measurement, control & protection
|
|
Lightning
Arrester
|
To discharge lightning over
voltages and switching over voltages to earth
|
|
Shunt
reactor
|
To control over voltages by providing
reactive power compensation
|
|
Neutral-Grounding
resistor
|
To limit earth fault current
|
|
Coupling
capacitor
|
To provide connection between high
voltage line & PLCC equipment
|
|
Line
–Trap
|
To prevent high frequency signals
from entering other zones.
|
|
Shunt
capacitors
|
To provide compensations to reactive
loads of lagging power factors
|
|
Power
Transformer
|
To step-up or step-down the voltage
and transfer power from one a.c. voltage another a.c. voltage at the same frequency.
|
|
Series
Capacitor
|
Compensation of long lines.
|
What is REF relay?
It is restricted earth fault relay. When the fault occurs very near to the neutral point of the transformer, the voltage available to drive the earth circuit is very small, which may not be sufficient to activate the relay, unless the relay is set for a very low current. Hence the zone of protection in the winding of the transformer is restricted to cover only around 85%. Hence the relay is called REF relay.
What are the errors in Current Transformer?
(a) Ratio error
Percentage ratio error = [(Nominal ratio – Actual ratio)/Actual ratio] x 100
The value of transformation ratio is not equal to the turns ratio.
(b) Phase angle error:
Phase angle =180/π[(ImCos δ-I1Sin δ)/nIs]
Percentage ratio error = [(Nominal ratio – Actual ratio)/Actual ratio] x 100
The value of transformation ratio is not equal to the turns ratio.
(b) Phase angle error:
Phase angle =180/π[(ImCos δ-I1Sin δ)/nIs]
What is an arc? Give the two methods of arc interruption?
Arc is a phenomenon occurring when the two contacts of a circuit breaker separate under heavy load or fault or short circuit condition.
Methods of arc interruption:
- High resistance interruption:-the arc resistance is increased by elongating, and splitting the arc so that the arc is fully extinguished
- Current zero method:-The arc is interrupted at current zero position that occurs 100 times a second in case of 50Hz power system frequency in ac.
What do you mean by current chopping?
When interrupting low inductive currents such as magnetizing currents of transformer, shunt reactor, the rapid deionization of the contact space and blast effect may cause the current to be interrupted before the natural current zero. This phenomenon of interruption of the current before its natural zero is called current chopping.
How to calculate voltage drop?
How to calculate voltage drop:
Single-phase voltage drop calculation:
Three-phase voltage drop calculation:
In situations where the circuit conductors span large distances, the voltage drop is calculated. If the voltage drop is too great, the circuit conductor must be increased to maintain the current between the points. The calculations for a single-phase circuit and a three-phase circuit differ slightly.
Single-phase voltage drop calculation:
Three-phase voltage drop calculation:
OR 3øVD = (SQRT( 3) *L*R*I) /1000
VD = Voltage drop (conductor temp of 75°C) in volts
VD% = Percentage of voltage drop (VD ÷ source voltage x 100). It is this value that is commonly called "voltage drop" and is cited in the NEC 215.2( A) (4) and throughout the NEC.
L = One-way length of the circuit's feeder (in feet)
R = Resistance factor per NEC Chapter 9, Table 8, in ohm/kft
I = Load current (in amperes)
Source voltage = The voltage of the branch circuit at the source of power. Typically the source voltage is either 120, 208, 240, 277, or 480 V.
Related Link: How much voltage drop is Acceptable?
Related Link: How much voltage drop is Acceptable?
How much voltage drop is Acceptable?
The national Electrical Code (NEC) recommends that the combined voltage drop of the electrical system (brunch circuit and feeders) not exceed 5% for optimum efficiency. This recommendation not only can improve safety but can ensure proper equipment operation and power efficiency. Foe Example, In a 220 volt 5 ampere circuit, this means that there should be no more than a 11 V drop (109 volts) at the furthest outlet when the circuit is fully loaded.
Related Link: How to calculate voltage drop?
July 5, 2013
What are the Components of the power system?
The various components of power system are:
- Generator (alternator),
- Transformer,
- Transmission line,
- Induction motor,
- Synchronous motor,
- Resistive and
- Reactive loads.
June 8, 2013
Mention The major features of a good protective gear for alternator and transformer
Major
features of a good protective gear
ü High
speedy
ü Selectivity
ü High
sensitivity
ü Stability
ü Simplicity
ü Reliability
Write down the Protective System of Alternator and Transformer
Alternator
protection
ü Differential
protection system
ü Balanced
Earth fault protection
ü Stator-inter
run protection
Transformer
protection
ü Using
Buchholz relay
ü Combined
leakage and overload protection
ü Circulating-current
scheme for transformer protection
Write down some major Faults of Alternator and Transformer.
12:49 AM
Alternator, Generator, Power Station, Power System, Switchgear and Protection, Transformer
No comments
Major faults in Alternator
- ü Failure of prime-mover
- ü Failure of field
- ü Over Current
- ü Over Voltage
- ü Over Speed
- ü Stator Winding faults
- ü Unbalanced
loading
Major faults in
Transformer
ü Open
circuits
ü Over
heating
ü Earth
Fault
ü Phase-to-Phase
fault
ü Over
Load
ü Phase
to ground fault
ü Incipient
fault
ü High
voltage surge fault
How can a circuit element absorb power?
By converting electrical energy into-
- Heat (resistors in toasters);
- Light (light bulbs);
- Acoustic energy (speakers);
- Storing energy (charging a battery).
June 2, 2013
May 30, 2013
Write down some Elements of Protection System.
Protection System Elements:
¤ Protective relays
¤ Circuit
breakers
¤ Current and
voltage transducers
¤ Communications
channels
¤ DC supply
system
¤ Control
cables
How Do Relays Detect Faults?
¤ When a
fault takes place, the current, voltage, frequency, and other electrical
variables behave in a peculiar way. For example:
o
Current suddenly increases
o
Voltage suddenly decreases
¤ Relays can
measure the currents and the voltages and detect that there is an overcurrent,
or an undervoltage, or a combination of both
¤ Many other
detection principles determine the design of protective relays
February 12, 2013
Write down some common applications of Diodes.
Some common applications of Diodes:
- Power supply applications
- AM (amplitude modulation) detectors
- Back-EMF path
- Clamping or DC restoration
- Clipper or limiter
- Non-linear circuits
- Logic circuits
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